Translate formula quotation marks incl. replacements into VBA-readable formulae
Translate formula quotation marks incl. replacements into VBA-readable formulae
I was inspired to write this post by the recent question of formula substitution using a constant. At the same time, the frequent problem emerged that quotation marks within a formula string should be replaced by double quotation marks in order to make them readable in VBA.
Practical use case
A practical use case is to copy a table formula directly from a SO website and "translate" it into a string-readable format.
But how is this supposed to be done with VBA means, since the direct input of such an incomplete formula string in a procedure code without manually added double quotation marks would immediately lead to an error?
Another feature would be to make replacements at certain points within a formula template, for example with a constant or even with several numerically identifiable markers.
I found a quick & dirty solution (without error handling) by analyzing a FormulaContainer
procedure containing exclusively outcommented formulae as these would allow any prior direct code input. In order to distinguish them from the usual commentaries, I decided with a heavy heart to use the Rem
prefix (i.e. Remark) as an alternative, which we may still be familiar with from ancient Basic times.
My intention is not to show a perfect solution, but to stimulate further solutions by demonstrating a possible way.
Question
Are there other work arounds allowing to copy tabular formulae with quotation marks directly and as possible replacement pattern into VBA procedures?
///////////////////////////////////
Main function QuickFormula()
References a FormulaContainer procedure containing exclusively formulae with Rem
prefixes, such as e.g.
Sub FormulaContainer()
Rem =....
Rem =....
End Sub
This allows formula inputs with quotation marks similar to tabular cell inputs; furthermore these inputs may contain string identifiers facilitating wanted replacements.
Option Explicit
'Site: https://stackoverflow.com/questions/70399681/how-many-quotes-to-put-around-a-formula-that-is-sending-an-empty-string
'Auth: https://stackoverflow.com/users/6460297/t-m
Function QuickFormula(ByVal no As Long, ParamArray repl() As Variant) As String
'Purp: - change indicated code line in FormulaContainer to code readable string and
' - replace enumerated identifiers with given value(s)
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
'1) get REMark code line indicated by ordinal argument no
QuickFormula = getCodeLine("modFormula", "FormulaContainer", no)
'2a)replace "#" identifyer(s) with constant repl value
If Not IsArray(repl(0)) Then
QuickFormula = Replace(QuickFormula, "{1}", "#")
QuickFormula = Replace(QuickFormula, "#", repl(0))
If Len(QuickFormula) = 0 Then QuickFormula = "Error NA!"
Debug.Print no & " ~~> " & Chr(34) & QuickFormula & Chr(34)
Exit Function
End If
'2b)replace 1-based "{i}" identifiers by ParamArray values
Dim i As Long
For i = LBound(repl(0)) To UBound(repl(0))
QuickFormula = Replace(QuickFormula, "{" & i + 1 & "}", repl(0)(i))
Next
'3) optional display in immediate window
Debug.Print no & " ~~> " & Chr(34) & QuickFormula & Chr(34)
End Function
Help function getCodeLine()
Gets a given code line of the indicated procedure
Function getCodeLine(ByVal ModuleName As String, ByVal ProcedureName As String, Optional ByVal no As Long = 1) As String
'Purp: return a code line in given procedure containing "Rem "
'Note: assumes no line breaks; needs a library reference to
' "Microsoft Visual Basic for Applications Extensibility 5.3"
Const SEARCH As String = "Rem =", QUOT As String = """"
'1) set project
Dim VBProj As Object
Set VBProj = ThisWorkbook.VBProject
If VBProj.Protection = vbext_pp_locked Then Exit Function ' escape locked projects
'2) set component
Dim VBComp As Object
Set VBComp = VBProj.VBComponents(ModuleName)
Dim pk As vbext_ProcKind
'3) get no + 3 top code line(s)
With VBComp.CodeModule
'a)count procedure header lines
Dim HeaderCount As Long: HeaderCount = .ProcBodyLine(ProcedureName, pk) - .ProcStartLine(ProcedureName, pk)
'b) get procedure code
Dim codelines
'codelines = Split(.Lines(.ProcBodyLine(ProcedureName, pk), .ProcCountLines(ProcedureName, pk) - HeaderCount), vbNewLine)
codelines = Split(.Lines(.ProcBodyLine(ProcedureName, pk), no + 1), vbNewLine)
'c) filter code lines containing "Rem" entries
codelines = Filter(codelines, SEARCH, True)
End With
'4) return (existing) codeline no
If no - 1 > UBound(codelines) Then Exit Function ' check existance
getCodeLine = Replace(Replace(codelines(no - 1), QUOT, String(2, QUOT)), "Rem =", "=")
End Function
Example call
References all three formulae in the FormulaContainer
(including an example of a non-existing number):
Sub EnterFormula()
With Sheet1.Range("X1") ' << change to any wanted target range
.Offset(1).Formula2 = QuickFormula(1, 6)
.Offset(2).Formula2 = QuickFormula(2, Array(10, 20, 30))
'two single argument inputs with same result
.Offset(3).Formula2 = QuickFormula(3, Array(17))
.Offset(4).Formula2 = QuickFormula(3, 17)
'not existing formula number in Rem code container
.Offset(5).Formula2 = QuickFormula(333, 17)
End With
End Sub
Example FormulaContainer
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
'Purp: formula container to be adjusted to code readable strings
'Note: Insert only Formulae starting with "Rem "-prefix!
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
' # identifies constant replacement(s)
' {i} stands for enumerated replacements {1},{2}..{n}
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Sub FormulaContainer()
Rem =IF($V#>0,IF($G#>$S#,($S#-$H#)*$K#+$Y#,($G#-$H#)*$K#+$Y#),"")
Rem =A{1}*B{3}+C{2}
Rem =A{1}+100
End Sub
Example output in immediate window
1 ~~> "=IF($V6>0,IF($G6>$S6,($S6-$H6)*$K6+$Y6,($G6-$H6)*$K6+$Y6),"""")"
2 ~~> "=A10*B30+C20"
3 ~~> "=A17+100"
3 ~~> "=A17+100"
333 ~~> "Error NA!"
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