Break a array into n chunks with overlapping start element

Hi everyone I have the following problem, I need to split an array into n even chunks, but the first element of every array except the first is the last element of the previous array. The last array can have a smaller number of elements if there aren't enough elements.

Input:

[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11]

Expected output n=3:

[[1, 2, 3, 4, 5], [5, 6, 8, 9, 10], [10, 11]]

I need a solution in javascript but feel free to submit other languages, I will translate it and submit the solution in js.

Thanks in advance have a great day :)

My not working attempt, I couldn't figure out how to start with desired chunk number so I used chunk size here with intention to figure out chunk size from chunk number later

let array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11];
const range = 4;
const res = [array.slice(0, range)];

let start = range;
let end = range * 2;
while (true) {
  console.log(start, end);
  res.push(array.slice(start, end));
  start += range;
  end += range;
  if (start >= array.length) {
    break;
  }
}

console.log(res);

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