How to make a program back to a certain line? (new programmer)

By -

I'm a computer programming student in High School looking for some help, in this assignment I have to make a choose your own ending game using if statements, I want to make it so when the user inputs a certain choice it will go to the next statement, but the thing is the statement is behind the one I want to add is a few statements behind, here's what I have so far...

System.out.println("senario1"
                + "\n"
                + "\n1) choice1"
                + "\n2) choice2");
        int choice3 = key.nextInt();

if (choice3 == 1)
        {
System.out.println("senario2"
                + "\n"
                + "\n1) choice3"
                + "\n2) choice4"
                + "\n3) choice5");
        int choice4 = key.nextInt();
            if (choice4 == 3)
            {

            }
        }
        else if (choice3 == 2)  
        {
        System.out.println("senario3"
                + "\n"
                + "\n1) choice6."
                + "\n2) choice7."
                + "\n3) choice8."
                + "\n4) choice9.");
        }

I want to make it so that if the user chooses choice3 it will send them to senario3 instead of continuing forward. I tried to do a one of those while-continue ones but I couldn't figure it out and from reading up I don't think that's the right solution. Any help is appreciated! I'm using Java and my IDE is Eclipse if that helps at all.

Explain to me like a baby because I am dumb! Thank you in advance!



from Recent Questions - Stack Overflow https://ift.tt/3dDwDAX
https://ift.tt/eA8V8J

Comments

Post a Comment

Popular posts from this blog

Today Walkin 14th-Sept

By -
Image
14th Sept 2017 ( GO Through all List) Read Walkin details properly , Try to call company before attending if possible !!! ==================================== 1. Myntra through fresherworld (Call Based , Venue shared to shortlisted candidates) _____________________________ 2. Magna : Hiring for Client Harman : C++
Read more

Hibernate Search - Elasticsearch with JSON manipulation

By -
Elasticsearch with JSON manipulation Elasticsearch ships with many features. It is possible that at some point, one feature you need will not be exposed by the Search DSL. To work around such limitations, Hibernate Search provides ways to: Transform the HTTP request sent to Elasticsearch for search queries. Read the raw JSON of the HTTP response received from Elasticsearch for search queries. Direct changes to the HTTP request may conflict with Hibernate Search features and be supported differently by different versions of Elasticsearch. Similarly, the content of the HTTP response may change depending on the version of Elasticsearch, depending on which Hibernate Search features are used, and even depending on how Hibernate Search features are implemented. Thus, features relying on direct access to HTTP requests or responses cannot be guaranteed to continue to work when upgrading Hibernate Search, even for micro upgrades (x.y.z to x.y.(z+1)). Use this at your own risk.
Read more

Spring Elasticsearch Operations

By -
Elasticsearch Operations Spring Data Elasticsearch uses two interfaces to define the operations that can be called against an Elasticsearch index. These are ElasticsearchOperations and ReactiveElasticsearchOperations. Whereas the first is used with the classic synchronous implementations, the second one uses reactive infrastructure. The default implementations of the interfaces offer: Read/Write mapping support for domain types. A rich query and criteria api. Resource management and Exception translation. ElasticsearchTemplate The ElasticsearchTemplate is an implementation of the ElasticsearchOperations interface using the Transport Client. @Configuration public class TransportClientConfig extends ElasticsearchConfigurationSupport {   @Bean   public Client elasticsearchClient() throws UnknownHostException {                      Settings settings = Settings.builder().put("cluster.name", "elasticsearch").build();     TransportClient client = new P
Read more