How to get into each element in a nested list and compare it with the equivalent in all elements in another list?

I need to get into each element in a nested list and compare it with the equivalent in all elements in another list.

I have two nested lists:

LB=
[[1, 0, 1, 0],
[1, 1, 1, 1],
[0, 0, 1, 0]]

LK=
[[1, 0, 1, 0],
[0, 0, 1, 1],
[1, 1, 1, 1],
[0, 0, 1, 0],
[1, 1, 0, 0],
[0, 0, 0, 0] ]

Analysis flow:
I take the first sublist from LK (i.e., [1, 0, 1, 0]) and compare its individual elements (i.e., 1, 0, 1, 0) with subsequent elements from the sublists LB [1, 0, 1, 0], [1, 1, 1, 1], and [0, 0, 1, 0]. I then take the second sublist from LK (i.e., [0, 0, 1, 1]) and compare its individual elements (i.e., 0, 0, 1, 1) with the subsequent elements from the LB sublist [1, 0, 1, 0], [1, 1, 1, 1, 1], and [0, 0, 1, 0] I then take the third sublist from LK (i.e., [1, 1, 1, 1]) and compare its individual elements (i.e., 1, 1, 1, 1) with the subsequent elements from the LB sublist [1, 0, 1, 0], [1, 1, 1, 1, 1], and [0, 0, 1, 0]

Here is my attempt at the code, but I know it doesn't work properly and doesn't contain all the conditions.

for i in LK, LB:
    for j in i:
        while j < (len(LK)-1):
            if j == 0:
                j += 1
            elif j != 0:
                i += 1
            else:
                print(LB[i])

Additional conditions:

  • if a given element in a list in LK is equal to 0 and the digit at the same position in LB is also equal to 0 then proceed to compare the next digit in the given list. When you get to the end of the sublist in the LK list, i.e. you pass [1, 0, 1, 0] and the condition with zeroes is fulfilled, write me this element from the LB list
  • if given element in the list in LK is equal 0, but digit in the same position in the list LB is not equal 0 then skip this case and check another sublist from LB
  • if there is no element 0 in the list LK (list [1, 1, 1, 1]) then write a sublist from LB

We perform such an iteration for all the elements in the list LB comparing them with the sublists from LK.

In the analyzed example during the comparison:

  • the first sublist from LK ([1, 0, 1, 0]) => should be extracted from the list LB: [1, 0, 1, 0] and [0, 0, 1, 0]
  • the second sublist from LK ([0, 0, 1, 1]) => should be printed from the list LB: [0, 0, 1, 0]
  • the third sublist from LK ([1, 1, 1, 1, 1]) => should be printed from the lists LB: [1, 0, 1, 0], [1, 1, 1, 1] and [0, 0, 1, 0]
  • the fourth sublist from LK ([0, 0, 1, 0]) => should be printed from the list LB: [0, 0, 1, 0]
  • the fifth sublist from LK ([1, 1, 0, 0]) => no element should be written out from the list LB
  • sixth sublist from LK ([0, 0, 0, 0]) => no element should be written out from the list LB

Output: Displayed LB sublists that meet the conditions (LB sublists can be displayed in several sectors)



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