Array processing and Table handling with packed decimal in COBOL
I was practicing array processing and table handling and there's this output of my program that I don't understand.
01 TABLE-VALUES.
05 TABLE-ELEMENTS OCCURS 2 TIMES.
10 A-A PIC X(5).
10 A-B PIC S9(5)V99 COMP-3.
01 WS-STRING PIC X(10).
01 S PIC 99.
01 WS-COUNT PIC 99.
...
PROCEDURE DIVISION.
0000-MAIN.
DISPLAY 'HELLO WORLD'
MOVE '1234567890ABCDEFGHI' TO TABLE-VALUES
DISPLAY 'TABLE VALUES ' TABLE-VALUES
MOVE 0 TO WS-COUNT
INSPECT TABLE-VALUES TALLYING WS-COUNT FOR CHARACTERS
DISPLAY WS-COUNT
PERFORM 1000-PARA VARYING S FROM 1 BY 1 UNTIL S > 2
STOP RUN.
1000-PARA.
MOVE 'A-A(&&) = ' TO WS-STRING
INSPECT WS-STRING REPLACING FIRST '&&' BY S
DISPLAY WS-STRING A-A(S)
MOVE 'A-B(&&) = ' TO WS-STRING
INSPECT WS-STRING REPLACING FIRST '&&' BY S
DISPLAY WS-STRING A-B(S).
The output turned out to be:
HELLO WORLD
TABLE VALUES 1234567890ABCDEFGHI
18
A-A(01) = 12345
A-B(01) = 6 7 8
A-A(02) = 0ABCD
A-B(02) = 5 6 7
I don't understand how A-B(1) and A-B(2) turned out like that. Why are there spaces in between? Where did digit 9 go to?
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