Java program to parse xml file

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Solution:

Config.xml

 <note>

  <id>1</id>

  <description>Files</description>

  <path>C://x</path>

  

    <id>2</id>

  <description>Files</description>

  <path>C://y</path>

</note>

1. 
   
2. import java.io.File;
3. import org.w3c.dom.*;
4. 
   
5. import javax.xml.parsers.*;
6. 
   
7. 
   
8. public class XML {
10. 
    
11. public static void main(String[] args) {
12. try {
13.         File inputFile = new File("C://Config.xml");
14.         DocumentBuilderFactory dbFactory 
15.            = DocumentBuilderFactory.newInstance();
16.         DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
17.         Document doc = dBuilder.parse(inputFile);
18.         doc.getDocumentElement().normalize();
19.         NodeList nList = doc.getElementsByTagName("ID");
20.         for (int temp = 0; temp < nList.getLength(); temp++) {
21.            Node nNode = nList.item(temp);
22.            if (nNode.getNodeType() == Node.ELEMENT_NODE) {
23.               Element eElement = (Element) nNode;
24.               String description =  eElement.getElementsByTagName("description").item(0).getTextContent();
25.               System.out.println(description);
26.               String path = eElement.getElementsByTagName("path").item(0).getTextContent();
27.                
28.               final File folder = new File(path);
29.               for (final File fileEntry : folder.listFiles()) {               
30.              if (fileEntry.isDirectory()) {
31.               System.out.println(fileEntry.getAbsolutePath());
32.              } else { 
33.         System.out.println(fileEntry.getAbsolutePath());
34.               }   
35.          }
36.            }
37.         }
38.      } catch (Exception e) {
39.         e.printStackTrace();
40.      }
41. }
42. }